The correct order of spin multiplicity of various ions of manganese including its neutral state is 

Options

A. `Mn^(7+) gt Mn^(6+) gt  Mn^(4+) gt Mn^(2+) gt  Mn`
B. `Mn gt Mn^(2+) gt Mn^(4+) gt Mn^(6+) gt Mn^(7+)`
C. `Mn^(7+) lt Mn^(6+) lt Mn^(4+) lt Mn^(2+) = Mn`
D. All have equal spin multiplicity

Answer

C