Match the elements with their corresponding `IE_1`.
`{:("Column-I","Column-II"),((P) N ,(1) +800),((Q) O,(2) +900),((R) Be,(3) +1300),((S) B ,(4) +1400):}`

Options

A. `{:(P,Q,R,S),(2,3,1,4):}`
B. `{:(P,Q,R,S),(1,2,3,4):}`
C. `{:(P,Q,R,S),(4,3,2,1):}`
D. `{:(P,Q,R,S),(1,4,2,3):}`

Answer

To solve the problem of matching the elements with their corresponding first ionization energies (IE₁), we will analyze the given elements: Nitrogen (N), Oxygen (O), Beryllium (Be), and Boron (B). We will determine their first ionization energies based on their electronic configurations and periodic trends.

### Step-by-Step Solution:

1. **Identify the Elements and Their Electronic Configurations**:
- Nitrogen (N): 1s² 2s² 2p³
- Oxygen (O): 1s² 2s² 2p⁴
- Beryllium (Be): 1s² 2s²
- Boron (B): 1s² 2s² 2p¹

2. **Understand Ionization Energy (IE)**:
- Ionization energy is the energy required to remove the outermost electron from an atom in its gaseous state.
- Generally, ionization energy increases across a period (left to right) due to increased nuclear charge and decreased atomic size.

3. **Analyze the Trends**:
- **Beryllium (Be)**: Has a stable configuration (2s²), thus it has a higher ionization energy compared to Boron.
- **Boron (B)**: Has one electron in the 2p subshell (2s² 2p¹), which is easier to remove than a fully filled subshell.
- **Nitrogen (N)**: Has a half-filled p subshell (2p³), which is relatively stable, thus it has a higher ionization energy than Oxygen.
- **Oxygen (O)**: Has a higher ionization energy than Boron but lower than Nitrogen due to its smaller size.

4. **Rank the Elements Based on Ionization Energy**:
- Highest IE: Nitrogen (N)
- Next: Oxygen (O)
- Next: Beryllium (Be)
- Lowest: Boron (B)

5. **Match the Elements with Their Corresponding Ionization Energies**:
- Nitrogen (N) → +1400 (4)
- Oxygen (O) → +1300 (3)
- Beryllium (Be) → +900 (2)
- Boron (B) → +800 (1)

### Final Matching:
- P (N) → 4 (+1400)
- Q (O) → 3 (+1300)
- R (Be) → 2 (+900)
- S (B) → 1 (+800)

### Conclusion:
The correct matches are:
- P → 4
- Q → 3
- R → 2
- S → 1