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The formation of the oxide ion O^(2-)(g)...

The formation of the oxide ion `O^(2-)(g)` requires first an exothermic and then an endothermic step as shown below:
`O(g) + e^(-) to O^(-)(g) , DeltaH^(@) = -142kJ mol^(-1)`
`O^(-)(g) + e^(-) to O^(2-)(g), DeltaH^(@) = +844kJ mol^(-)1`
 Which is not the cause of the above fact? 

A

Oxygen is more electronegative.

B

Oxygen has high electron affinity.

C

`O^(-)` ion has comparatively larger size than oxygen atom.

D

`O^(-)` ion will tend to resist the addition of electron.

Text Solution

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The correct Answer is:
A, B
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The formation of the oxide ion O_((g))^(2-) requires first an exothermic and then an endothermic step as shown below. O_((g)) +e^(-) = O_((g))^(-) DeltaH^(@) =- 142 kJ mol^(-1) O_((g))^(-) + e^(-) = O_((g))^(2-) DeltaH^(@) = 844 kJ mol^(-1) This is because of :

The formation of the oxide ion O_(g)^(2-) requires first an exothermic and then an endothermic step as shown below: O_(g)+e^(-) rarr O_(g)^(-) , DeltaH=-142 kJ mol^(-1) O(g)+e rarr O_(g)^(2-) , DeltaH=844kJ mol^(-1) This is because: