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The answer to each of the following is a...

The answer to each of the following is a non-negative intcger.
The number equivalent Cl-, bonds in `Cl_2O_7` is…………

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The correct Answer is:
To determine the number of equivalent Cl-O bonds in the compound \( Cl_2O_7 \), we can follow these steps: ### Step 1: Understand the Structure of \( Cl_2O_7 \) The molecular formula \( Cl_2O_7 \) indicates that there are 2 chlorine (Cl) atoms and 7 oxygen (O) atoms. To analyze the bonding, we need to visualize or draw the structure of the molecule. ### Step 2: Draw the Lewis Structure 1. **Count Valence Electrons**: - Chlorine has 7 valence electrons, and there are 2 Cl atoms: \( 2 \times 7 = 14 \) electrons. - Oxygen has 6 valence electrons, and there are 7 O atoms: \( 7 \times 6 = 42 \) electrons. - Total valence electrons = \( 14 + 42 = 56 \) electrons. 2. **Construct the Structure**: - The structure of \( Cl_2O_7 \) can be represented as: - Two Cl atoms are bonded to a central arrangement of O atoms. - There are 3 double bonds between Cl and O, and the remaining O atoms are single-bonded to Cl. ### Step 3: Count the Equivalent Cl-O Bonds - In the structure, we find that there are 6 Cl-O bonds: - 3 double bonds contribute 6 equivalent Cl-O bonds. ### Step 4: Conclusion Thus, the number of equivalent Cl-O bonds in \( Cl_2O_7 \) is **6**. ### Final Answer The number of equivalent Cl-O bonds in \( Cl_2O_7 \) is **6**. ---
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