The answer to each of the following is a non-negative intcger.
The number equivalent Cl-, bonds in `Cl_2O_7` is…………

Answer

To determine the number of equivalent Cl-O bonds in the compound \( Cl_2O_7 \), we can follow these steps:

### Step 1: Understand the Structure of \( Cl_2O_7 \)
The molecular formula \( Cl_2O_7 \) indicates that there are 2 chlorine (Cl) atoms and 7 oxygen (O) atoms. To analyze the bonding, we need to visualize or draw the structure of the molecule.

### Step 2: Draw the Lewis Structure
1. **Count Valence Electrons**:
- Chlorine has 7 valence electrons, and there are 2 Cl atoms: \( 2 \times 7 = 14 \) electrons.
- Oxygen has 6 valence electrons, and there are 7 O atoms: \( 7 \times 6 = 42 \) electrons.
- Total valence electrons = \( 14 + 42 = 56 \) electrons.

2. **Construct the Structure**:
- The structure of \( Cl_2O_7 \) can be represented as:
- Two Cl atoms are bonded to a central arrangement of O atoms.
- There are 3 double bonds between Cl and O, and the remaining O atoms are single-bonded to Cl.

### Step 3: Count the Equivalent Cl-O Bonds
- In the structure, we find that there are 6 Cl-O bonds:
- 3 double bonds contribute 6 equivalent Cl-O bonds.

### Step 4: Conclusion
Thus, the number of equivalent Cl-O bonds in \( Cl_2O_7 \) is **6**.

### Final Answer
The number of equivalent Cl-O bonds in \( Cl_2O_7 \) is **6**.

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