The line `(x-3)/(1)=(y-2)/(2)=(z-k)/(2)` lies completely in the plane `2x-2y+z=0` for `k` equals

The line (x-4)/(1) =(2y-4)/(2)=(k-z)/(-2) lies exaclty in the plane 2x-4y+z=7 find the value of k

If the line (x-4)/(1)=(y-2)/(1)=(z-k)/(2) lies exactly on the plane 2x-4y+z=7 , the value of k is

If the line (x-1)/(2)=(y-3)/(a)=(z+1)/(3) lies in the plane bx+2y+3z-4=0 , then

The line (x-4)/1=(y-2)/1=(z-k)/2 lies exactly on the plane 2x-4y+z=7 then the value of k is (A) 7 (B) -7 (C) 1 (D) none of these

If the line (x-3)/3 = (y-1)/-2 = (z-c)/-8 lies in the plane 2x-y+z=10, then: c=

The value of K such that the line (x-4)/(1)=(y-2)/(1)=(z-k)/(2) lies in the plane 2x-4y+pz=7 is

Value of k such that the line (x-4)/1 = (y-2)/1 =(z-k)/2 lies in the plane 2x-4y+z=7 is

If the line (x-1)/(1)=(y-k)/(-2)=(z-3)/(lambda) lies in the plane 3x+4y-2z=6 , then 5|k|+3|lambda| is equal to