An open pipe is in resonance in 2nd harmonic with frequency `f_(1)`. Now one end of end of the tube is closed and frequency is increased to `f_(2)` such that the resonance again occurs in nth harmonic. Choose the correct option.

An open pipe is in resonance in 2nd harmonic with frequency f_(1) . Now one end of the tube is closed and frequency is increased to f_(2) such that the resonance again ocuurs in nth harmonic. Choose the corrct option

An open pipe is resonance is its 2^(nd) harmonic with tuning fork of freqency f_(1) . Now it is closed at one end. If the frequency of the tuning fork is increases slowly from f_(1) , then agaain a resonance is obtained with a_(1) frequency f_(2) . if in this case the pipe vibrates n^(th) harmonics, then

Second overtons frequency of a pipe and fourth harmonic frequency of an pipe are same. Then, choose the correct options.

For fundamental frequency f of a closed pipe, choose the correct options.

A tube of diameter d and of length l is open a both ends. Its fundamental frequnecy of resonance is found to be f_(1) . One end of the tube is now closed. The lowrst frequency of resonance of this closed tube is now f_(2) . Taking into consideration the end correction , (f2)/(f_(1) is

An open pipe resonates to a frequency n_1 and closed pipe to a frequency n_2 . If they are joined to form a longer closed pipes , then its fundamental frequency of resonance will be

The sharpness of resonance or Q value of resonant circuit with resonant frequency f_(r) and half power frequency f_(1) and f_(2) is