The third overtone of an open organ pipe of length `l_(0)` has the same frequency as the third overtone of a closed pipe of length `l_(c)`. The ratio `l_(0)//l_(c)` is equal to

The second overtone of an open organ pipe has the same frequency as the first overtone of a closed pipe L metre long. The length of the open pipe will be

if the first overtone of a closed pipe of length 50 cm has the same frequency as the first overtone of an open pipe, then the length of the open pipe is

The second overtone of an open pipe has the same frequency as the first overtone of a closed pipe 2 m long. The length of the open pipe is

The frequency of the third overtone of a closed pipe of length L_(c) is the same as the frequency of the sixth overtone of an open pipe of the length L_(o). Then

Fundamental frequency of an open pipe of length 0.5 m is equal to the frequency of the first overtone of a closed pipe of length l . The value of l_(c) is (m)

The frequency of the first overtons of a closed pipe of length l_(1) is equal to that of the first overtone of an open pipe of length l_(2) The ratio of their lengths (l_(1) : l_(2) is

The first overtone of an open organ pipe(of length L_(0) ) beats with the first overtone of a closed organ pipe(of length L_(c) ) with a beat frequency of 10Hz.The fundamental frequency of the closed pipe is 110Hz .If the speed of sound is 330ms then fundamental frequency of open pipe is ?