The space between the plates of a parallel plate capacitor of capacitance C is filled with three dielectric slabs of identical size as shown in figure. If the dielectric constants of the three slabs are `K_1 , K_2 and K_3` find the new capacitance.

A dielectric slab is placed between the plates of a parallel plate capacitor. Its capacitance

Space between the plates of a parallel plate capacitor is filled with a dielectric slab. The capacitor is charged and then the supply is disconnected to it. If the slab is now taken out then

A parallel plate capacitor of plate area A and spac- ing between the plates d is filled with three dielectrics as shown in the Figure. The dielectric constants of the three dielectrics are K_(1) = K, K_(2) = 2 K, K_(3) = 3 K . The capacitor is connected to a cell of emf V. (a) Write the ratio of maximum to minimum charge density on the surface of the capacitor plate. (b) Calculate the surface charge density of bound (induced) charge on the middle dielectric. (c) If the three dielectrics occupy equal volume between the plates, calculate the capacitance of the capacitor.

Explain why the capacitance of a parallel plate capacitor increases when a dielectric slab is introduced between the plates.

The separation between the plates of a parallel plate capacitor is d and the area of each plate is A. iff a dielectric slab of thickness x and dielectric constant K is introduced between the plates, then the capacitance will be

The capacitance of a capacitor, filled with two dielectrics of same dimensions but of dielectric constants K_1 and K_2 respectively as shown will be -

A parallel plate air capacitor has a capacitance C . When it is half filled with a dielectric (K=2) , the percentage increase in the cpacitance will be