The amplitude of damped oscillator becomes `1/3` in `2s`. Its amplitude after `6s` is `1//n` times the original. The value of `n` is

The amplitude of damped oscillator becomes half in one minute. The amplitude after 3 minutes will be 1//x times the original, where x is

The amplitude of a damped oscillator becomes half in one minutes. The amplitude after 3 minutes will be 1/x times of the original . Determine the value of x.

The amplitude (A) of damped oscillator becomes half in 5 minutes. The amplitude after next 10 minutes will be

The amplitude of a damped oscillator becomes (1)/(27)^(th) of its initial value after 6 minutes. Its amplitude after 2 minutes is

The amplitude of damped oscillator decreased to 0.9 times its original magnitude is 5s . In another 10s it will decrease to alpha times its original magnitude, where alpha equals.

The amplitude of a damped oscillation decreases to 0.8 times its original magnitude in 4s. In another 12s, it will decrease to n time its original magnitude. Find the value of n.

When a dampled harmonic oscillator completes 100 oscillations, its amplitude is reduced to (1)/(3) of its initial value. When will be its amplitude when it completes 200 oscillations?

Amplitude of a swing decreases to 0.5 times its original magnitude in 4s due to damping by air friction. Its amplitude becomes how many times of the original magnitude in another 8s?

If initial amplitude during a damped oscillation of mass m is 12 cm and after 2s it reduces to 6cm then find damping constant(b)