Solve for x, `sin[sin^(-1)(1/5)+cos^(-1)x]=1`

Solve for x : cos(2sin^(-1)x)=1/3

sin[cos^(-1)x]=cos[sin^(-1)x]

Solve sin{sin^-1((1)/(2))+cos^(-1)x}=1

Solve for x : i) cos(sin^(-1)x)=1/2 ii) tan^(-1)x=sin^(-1)1/sqrt(2) iii) sin^(-1)x-cos^(-1)x=pi/6

Solve sin^(-1)x<=cos^(-1)x

Solve : (i)" "tan^(-1). x/2 +tan^(-1). x/3 = pi/4 , sqrt(6) gt x gt 0 (ii)" "sin(sin^(-1) . 1/5+cos^(-1)x)=1

If: sin(sin^(-1)(1/5) + cos^(-1)x)=1 , then: x=

If sin(sin ""^(-1) [(1)/(5)] + cos^(-1) x) = 1 ,then x is