The distance of the plane `3x+4y+5z=10` from the origin is:

The distance of the plane 6x-3y+2z-14=0 from the origin is

Find the distance of the plane 3x-4y+12z=3 from the origin.

The distance of a plane 3x + 4y - 5z = 60 from origin

Find the distance of the plane 2x-3y+4z-6=0 from the origin.

Find the distance of the plane 2x - 3y + 4z = 6 from the origin.

If the perpendicular distance of the plane 2x+3y-z= k from the origin is sqrt(14) units then k=……..

Find the equation of the plane passing through the points (1,0,-2),(3,-1,0) and perpendicular to the plane 2x-y+z=8.Also find the distance of the plane thus obtained from the origin.

What is the perpendicular distance of plane 2x-y+3z =10 from origin

For each of the following planes, find the direction cosines of the normal to the plane and the distance of the plane from the origin: i) 2x+3y-z=5 , ii) z=3 , iii) 3y+5=0 .

Find the equation of the plane through the line of intersection of the planes x+y+z=1 and 2x+3y+4z=5 , which is perpendicular to the plane x-y+z=0 . Also find the distance of the plane so obtained from the origin.