A parallel plate air capacitor is charged to a potential difference of `V` volts. After disconnecting the charging battery the distance between the plates of the capacitor is increased using an isulating handle. As a result the potential difference between the plates

A parallel plate capacitor is charged to a potential difference of 10 volts. After disconnecting the battery, distance between the plates of capacitor is decreased by using nonconducting handles. The potential difference between the plates will

A parallel plate capacitor is charged by connecting it to a battery. Which of the following will remain constant if the distance between the plates of the capacitor is increased in this situation?

The plates of a parallel plate capacitor are charged to a potential difference of 117 V and then connected across a resistor. The potential difference across the capacitor decreases exponentially with to time.After 1s the potential difference between the plates is 39 V, then after 2s from the start, the potential difference (in V) between the plates is

A parallel plate capacitor of capacitance 2 muF is fully charged to a potential difference of 500 volts and then disconnected from the battery. Using insulating handles, separation between the paltes is made thrice the initial value. What will be the new potential difference between the plates of the capacitor and by what amount stored energy changes in this process?

A parallel plate capcitor of capacitance C is charged to a potential V by a battery. Without disconencting the battery = distance between the plates of capacitor is triple and a dielectric medium of K = 10 is introduced between the plates of capacitor. Explain giving reasons how will the following be affected ? (a) Capacitance of capacitor (b) Charge on capacitor (c ) Energy density of capacitor.

A parallel plate capacitor is charged to a potential difference of 50V. It is discharged through a resistance. After 1 second, the potential difference between plates becomes 40V. Then

A parallel plate capacitor is charged to a potential difference V by a dc source. The capacitor is then disconnected from the source. If the distance between the plates in doubled, state with reason how the following will change, (i) electric field between the plates, (ii) capacitance and (iii) energy stored in the capacitor.

A parallel plate capacitor is charged to a potential difference of 100V and disconnected from the source of emf. A slab of dielectric is then inserted between the plates. Which of the following three quantities change?

The plates of a capacitor are charged to a potential difference of 320 volt and are then connected across a resistor. The potential difference across the capacitor decays exponentially with time. After 1 sec the potential difference between the plates of the capacitor is 240 volts. what is the potential difference between the plates after 2 s?