A parallel plate capacitor has plate of area `A` and separation`d` .It is charged to a potential difference `V_(0)` . The charging battery is disconnected and the plates are pulled apart to three times the initial separation.The work required to separate the plates is.

A parallel plate capcitor has plate area A and separation d . It is charged to a potential difference V_(0) . The charging battery is disconnected and the plates are pulled apart to three times the initial separation. The work required to separate the plates is

A pararllel plate capacitor has plates of area A and separation d and is charged to potential diference V . The charging battery is then disconnected and the plates are pulle apart until their separation is 2d . What is the work required to separate the plates?

A parallel-plate capacitor has plates of area A and separation d and is charged to a potential difference V . The charging battery is then disconnected, and the plates are pulled apart until their separation is 2d . Derive expression in terms of A, d and V for (a) the new potential difference (b) the initial and final stored energies, U_i and U_f and (c) the work required to increase the separation of plates from d to 2d .

A parallel plate capacitor of plate are A and plate separation d is charged by a battery of voltage V. The battery is then disconnected. The work needed to pull the plates to a separation 2d is

A parallel plate capacitor having plate area A and separation between the plates d is charged to potential V .The energy stored in capacitor is ....???

A parallel plate capacitor has plates with area A and separation d. A battery charges the plates to a potential difference V_(0) . The battery is then disconnected and a dielectric slab of thikness d is introduced. The ratio of the enrgy stored in the capacitor before and after the slab is introduced, is

A parallel - plate capacitor of plate area A and plate separation d is charged to a potential difference V and then the battery is disconnected . A slab of dielectric constant K is then inserted between the plate of the capacitor so as to fill the space between the plate .Find the work done on the system in the process of inserting the slab.

A parallel plate capacitor is charged. If the plates are pulled apart

A parallel plate capacitor of plate area A and plate separation d is charged to potential difference V and then the battery is disconnected. A slab of dielectric constant K is then inserted between the plates of the capacitor so as to fill the space between the plates. If Q, E and W denote respectively, the magnitude of charge on each plate, the electric field between the plates (after the slab is inserted), and work done on the system, in question, in the process of inserting the slab, then

A capacitor C is charged to a potential difference V and battery is disconnected. Now if the capacitor plates are brough close slowely by some distance: