find the value of a so that th volume fo a so that the valume of the parallelepiped formed by vectors `hati=ahatj+hatk,hatj+ahatkandahati+hatk` becomes minimum.

The value of a so that the volume of the paralelopiped formed by hati+ahatj+hatk, hatj+ahatk and ahati+hatk becomes minimum is

The value of a, such that the volume of the parallelopiped formed by the vectors hati+hatj+hatk, hatj+ahatk and ahati+hatk becomes minimum, is

The value of the a so that the volume of the paralellopied formed by vectors hatiahatj+hatk,hatj+ahatk,ahati+hatk becomes minimum is (A) sqrt(3) (B) 2 (C) 1/sqrt(3) (D) 3

The value of a so thast the volume of parallelpiped formed by vectors hati+ahatj+hatk, hatj+ahatk, ahati+hatk becomes minimum is (A) sqrt93) (B) 2 (C) 1/sqrt(3) (D) 3

Find the value of lambda for which the volume of parallelepiped formed by the vector hati+lambda hat j+hat k. hatj+lambda hatk and lambda hti + hatk is minimum.

The volume of the parallelepiped formed by the vectors, veca=2hati+3hatj-hatk, vecb = hati-4hatj+2hatk and vecc=5hati+hatj+hatk is

The valume of the parallelopiped whose coterminous edges are hati-hatj+hatk,2hati-4hatj+5hatk and 3hati-5hatj+2hatk , is

Find the value of m so that the vector 3 hati - 2hatj +hatk is perpendicular to the vector. 2hati +6hatj +m hatk .