A body of mass 5 kg is acted upon by two perpendicular forces 8 N and 6 N . Give the perpendicular forces 8 N and 6 N .Give the magnitude and direction of the acceleration of the body ?

Explanation

Here m = 5kg , `vec(a) = 2 `
`vec(F)_(1) =vec(OA)= 8N`
`vec(F)_(2) = vec(OB) = 6N `
Resultant force ,
`vec(F) = vec(OC) = sqrt(F_(1)^(2)+F_(2)^(2))=sqrt(8^(2)+6^(2))`10 N
If `angle AoC = theta , tan theta = (AC)/(OA) = (OB)/(OA) = 6/8 = 0.75`
` theta = 36^(@) 52`
This the direction of resultant force and hence the direction of acceleration of the body fig .
Also `a = F/m = 10/5 = 2 ms^(-2)`