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Figure shows the position - time graph ...

Figure shows the position - time graph of a body of mass `0.04` kg . Suggest a suitable physical context for this motion . What is the time between by the body ? What is the magnitude of each impulse ?

Text Solution

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Here , m = 0.04 kg position time graph shows that the particle moves from x = 0 at 0 to x = 2 cm at A in 2 sec .
As `x - t` graph is a st. line the motion is with a constant velocity .

From x = 2 cm at A , particle goes to x = 0 at B in 2 sec .
As AB is stline , motion is with constant velocity N = 1 cm/s
velocity N = 1 cm/s
` - 10^(-2)` m/s Negative sign indicates the reversal of direction of motion . thsi is being repeated .We can visualise a ball moving between two walls located at x = 0 and x = 2 cm , getting rebounded repeatedly on striking against each wall on every collision with a wall , linear momentum of the ball changes . Therefore , teh ball receives impulse after every two seconds . Magnitude of impulse = Total change in lineas momentum .
` = "mu" - (mv)`
`= "mu" - mv = m(u-v)`
`= 0.04 (10^(-2) +10^(-2))`
` = 0.08 xx10^(-2)`
`= 8 xx 10^(-4) ` kg m/s .
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Knowledge Check

  • The position-time graph of a body of mass 0.04 kg. Suggest a suitable physical context for this motion. The time between two consecutive impulses received by the body, the magnitude of each impulse is:

    A
    4 sec, `4 xx 10^(-4)` kg m/s
    B
    2 sc, `8 xx 10^(-4)` kg m/
    C
    6 sec, `4 xx 10^(-4)` kg m/s
    D
    8 sec, `8 xx 10^(-4)` kg ms
  • Velocity - time graph for a body of mass 10 kg is shown in figure. Work - done on the body in first two seconds of the motion is :

    A
    `-9300 j`
    B
    1200 j
    C
    `-4500 j`
    D
    `-1200 j`
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