A stone of mass `0.1` kg is thrown vertically upwards .Give the magnitude and direction of the net force on the stone (a) during its upward motion. (b) During the downward motion . (c ) at the highest point, where it momentarily comes to rest .

Explanation

Given that mass of stome m = 0.1 kg , g = `9.8 ms^(2)`
(a) During upward motion : Magnitude of net force on the stone ,
F = `|-mg|, F= 0.1 xx 9.8 = 0.98 N `
Direction of net force is in upward direction .
(b) During downward motion : Magnitude of nwt force on the stone ,
= mg = `0.1 xx 9.8 = 0.98 N `
Direction of net force is in downward direction .
(c )Ath the heighest point : Magnitude of net force , F = mg = `0.1 xx 9.8 = 0.98 N `
At highest point of stone , dirrection is indeterminate .