How many Cl atoms can you ionize in the process `Cl to Cl^(+) + e` by the energy liberated for the process `Cl + e to Cl^(-)` for one Avogadro number of atoms. Given IP = 13.0 eV, and EA = 3.60 eV. Avogadro number = `6 xx 10^(23)`.

Explanation

Given `Cl_((g)) + e^(-) rarr Cl_((g))^(-) " " Delta H= 03.6eV`
1-atm `rarr` Electron affinity = 3.6eV
`6.023 xx 10^(23)rarr` ?
`6.023 xx 10^(23) xx 3.6 = 21.6828 xx 10^(23)`
`therefore` For one avagadro no. of Cl atoms electron affinity `=21.6828 xx 10^(23) eV`
Given 13 eV can ionise 1 atom of Cl
`21.6828 xx 10^(23)eV` ionise-?
`(21.6828 xx 10^(23))/(13)=1.667 xx 10^(23)` atoms