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The electron affinity of chlorine is 3.7...

The electron affinity of chlorine is 3.7 eV. How much energy in kcal is released when 2g of chlorine atoms is completely converted to `Cl^(-)` ions in the gaseous state?
`(1 eV = 23.06 Kcal)`.

Text Solution

Verified by Experts

Given electron affinity of Cl= 3.7eV
`Cl + e^(-) rarr Cl^(-) " " Detla H= -3.7ev`
35.5 gms of Cl contains `6.023 xx 10^(23)` atoms
2gms of Cl contains? `=(2 xx 6.023 xx 10^(23))/(35.5)` atoms
`6.023 xx 10^(23)` atoms can liberate 3.7eV
`(2 xx 6.023 xx 10^(23))/(35.5)` atom can liberate?
`=(2 xx 6.023 xx 10^(23) xx 3.7)/(35.5 xx 6.023 xx 10^(23))=(2 xx 3.7)/(35.5)= (7.4)/(35.5)`
=0.2084 eV `=0.2084 xx 23.06` kcal/mole
=4.81 k.cal/mole
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