Critical temperature for carbon dioxide and methane are `31.1^@C` and `-81.9^@C` respectively. Which of these has stronger intermolecular forces and why?

Explanation

Given Critical temperatures of `CO_2, CH_4`,
` T_C (CO_2) = 31.1^@ C `
` T_C (CH_4) =- 81.9^@ C `
` to ` The gas with highest critical temperature value can be easily liquified because of high inter molecular forces.
` therefore T_(C) (CO_2) ` is very high
So ` CO_2` gas liquified easily
` to ` .He gás has low `T_c` value so it is highly difficult to liquify.