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Find out the value of equilibrium consta...

Find out the value of equilibrium constant for the following reaction at 298 K.
`2NH_(3(g)) + CO_(2(g)) standard Gibbs energy change, `DeltaG^@` at the given temperature is `- 13.6 kJ mol^(-1)`.

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Verified by Experts

We know log `K=(triangle_(r) G^@)/(2.303 RT)`
`=(-13.6 xx 10^(3) "J mol"^(-1))/(2.303 (8.314 JK^(-1) mol^(-1)) (298 K))`
=2.38
Hence K=antilog 2.38= `2.4 xx10^2`.
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