Home
Class 11
MATHS
A window is in the shap of a rectangle s...

A window is in the shap of a rectangle surmounted by a semicircle. If the perimeter of the window is 20 ft, find the maximum area.

Promotional Banner

Topper's Solved these Questions

  • TELANGANA MARCH 2015

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise Section - B (Short answer type questions)|7 Videos

  • STRAIGHT LINE

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise TEXTUAL EXERCISES (EXERCISE-3(e)) |32 Videos

  • THE PLANE

    VIKRAM PUBLICATION ( ANDHRA PUBLICATION)|Exercise IMPORTANT POINTS |4 Videos

Similar Questions

Explore conceptually related problems

A window is in the shape of a rectangle surmounted by a semi-circle. If the perimeter of the window be 20 feet then find the maximum area.

Find the perimeter of the rectangle .

Length of a rectangle exceeds its breadth by 4 m. If the perimeter of the rectangle is 84 m, find its length and breadth.

Length of a rectangle exceeds its breadth by 4 m. If the perimeter of the rectangle is 84m, Find its length and breadth.

Length of a rectangle is 8 m less than twice its breadth. If the perimeter of the rectangle is 56 m, Find its length and breadth.

The perimeter of a sector is 24 cm. Its maximum area in sq.cm is