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One mole of ethanol is produced reacting...

One mole of ethanol is produced reacting graphite, `H_(2) and O_(2)` together. The standard enthalpy of formations is `-277.7kJ mol^(-1)`. Calculate the standard enthalpy of the reaction when 4 moles of graphite is involved

A

`-277.7`

B

`-555.4`

C

`-138.85`

D

`-69.42`

Text Solution

Verified by Experts

The correct Answer is:
B
The related equation for the formation of ethanol is. 2C (graphite) `3H_(2)(g) + (1)/(2) O_(2)(g) rarr C_(2)H_(5)OH(l), Delta H_(f)= -277.7` kJ/mol
When 2 moles of graphite is involved the standard enthalpy of reaction is `-277.7`kJ/mol
`therefore` When 4 moles of graphite is involved, standard enthalpy of reaction is `2 xx (-277.7kJ//"mol")` =`(-)` 555.4 kJ/mol
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