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If 1 mol of NaCl solute is dissolved int...

If 1 mol of NaCl solute is dissolved into the 1kg of water, at what temperature will water boil at 1.013 bar? (`K_(b)` of water is 0.52 K kg `mol^(-1)`)

A

373.15K

B

373.67K

C

374.19K

D

373.19K

Text Solution

Verified by Experts

The correct Answer is:
B
`because Delta T= K_(b) (n)/(W_(A))`
Given, `K_(b)= 0.52K kg mol^(-1)`
n=1, `w_(A)= 1kg`
`therefore Delta T= (0.52 xx 1)/(1)= 0.52K`
`because` Boiling point of pure water at 1.013 bar (i.e. 1 atm) is 373.15K
`therefore` Boiling point of the solution = `373.15+0.52=373.67K`
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