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At a certain temperature, 1.0 mole of PC...

At a certain temperature, 1.0 mole of `PCl_(3(g))` and 2.0 mole of `Cl_(2(g))` were placed in a 3.0 litre container. When equilibrium is reached, only 0.70 mole of `PCl_(3(g))` remained unreacted. Calculate the value of `K_c` for the reaction, `PCl_(3(g)) +Cl_(2(g)) Leftrightarrow PCl_(5(g))`

A

0.76

B

0.076

C

0.38

D

1.52

Text Solution

Verified by Experts

The correct Answer is:
A
`"Initial moles " underset(1)(PCl_(3(g)) +underset(2)(Cl_(2(g)) Leftrightarrow underset(0)(PCl_(5(g))`
`"Equil. moles 1-0.3 2-0.3 0.3"`
`"Conc. at equili. "(0.7)/3" "(1.7)/3" "(0.3)/3`
`K_(c)=([PCl_5])/([PCl_3] [Cl_2])=(0.3//3)/((0.7)/3 xx (1.7)/3) =(0.9)/(0.7 xx 1.7)=0.76`
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