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4.5 moles each of hydrogen and iodine we...

4.5 moles each of hydrogen and iodine were heated in a sealed 10 litre vessel. At equilibrium, 3 moles of HI were found. The equilibrium constant for `H_(2(g)) +I_(2(g)) Leftrightarrow 2HI_((g))` is

A

1

B

10

C

5

D

0.33

Text Solution

Verified by Experts

The correct Answer is:
A
2 moles of HI are found from 1 mole of `H_2 and I_2`
`"Initial moles "underset(4.5)(H)+underset(4.5)(I_(2)) Leftrightarrow underset(0)(2HI)`
`"At equilibrium 3 3 3"`
`K=([HI]^2)/([H_(2)][I_(2)])=(3)^2/(3 xx 3)=1`
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