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What is the equilibrium expression for t...

What is the equilibrium expression for the reaction `P_(4(s))+5O_(2(g)) Leftrightarrow P_(4)O_(10(s))?`

A

`K_(c)=([P_(4)O_(10)])/([P_(4)] [O_(2)])`

B

`K_(c)=1/([O_(2)]^5)`

C

`K_(c)=[O_(2)]^5`

D

`K_(c)=([P_(4)O_(10)])/(5[P_(4)] [O_(2)])`

Text Solution

Verified by Experts

The correct Answer is:
B
`P_(4(s)) +5O_(2(g)) Leftrightarrow P_(4)O_(10(s))`
Since concentration of solids is taken as unity.
`K_(c)=1/([O_(2)]^5)`
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The equilibrium constant for the reaction? P_(4(s)) +5 O_(2(g)) rarr P_(4)O_(10(s)) (A) k_(p) =(1)/ (p_(o_(2))^(5)) (B) k_(p) = p_(o_(2))^(5) (C) k_(p) = (P_(P_(4)o_(10))) / (p_(p_(4)) p_(o_(2))^(5)) (D) k_(p) = (p_(p_(4)) * p_(o_(2))^(5)) / (P_(p_(4)o_(10))) ]