Home
Class 11
CHEMISTRY
Phosphorus pentachloride dissociates as ...

Phosphorus pentachloride dissociates as follows, in a closed reaction vessel, `PCl_(5(g)) Leftrightarrow PCl_(3(g))+Cl_(2(g))`
If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of `PCl_5` is x, the partial pressure of `PCl_3` will be

A

`((x)/(x+1))P`

B

`((2x)/(1-x))P`

C

`((x)/(x-1))P`

D

`((x)/(1-x))P`

Text Solution

Verified by Experts

The correct Answer is:
A
`pcL_(5) Leftrightarrow PCl_3+Cl_2`
`t_(0)" 1 0 0"`
`t_(eq)" 1-x x x"`
`p_(PCl_3)` =Total pressure `xx` Mole fraction of `PCl_3`
`PCl_3=P. ((x)/(1+x))`
Promotional Banner

Similar Questions

Explore conceptually related problems

Phosphorus pentachloride dissociates as follows, ina closed reaction vessel, PC1_(5(g))hArrPC1_(3(g)) + C1_(2(g)) If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PC1_(5) is x, the partial pressure of PC1_(3) will be:

Phosphorus pentachloride dissociates as follows in a closed reaction vessel. PCl_5(g) hArr PCl_3(g) +Cl_2(g) If total pressure at equilibrium of the reactions mixture is P and degree of dissociation of PCl_5 is x, the partial pressure of PCl_3 will be:

Phosphorous pentachloride dissociates as follows (in a closed reaction vessel): PCI_(5)(g)hArrPCI_(3)(g)+CI_(2)(g) If the total pressure at equilibrium on the reaction mixture is P and the degree of dissociation of PCI_(5) is x, the partial pressure of PCI_(3) will be

PCl_(5) dissociation a closed container as : PCl_(5(g))hArrPCl_(3(g))+Cl_(2(g)) If total pressure at equilibrium of the reaction mixture is P and degree of dissociation of PCl_(5) is alpha , the partial pressure of PCl_(3) will be:

The degree of dissociation of PCl_(5) will be more at ………. pressure.

The degree of dissociation of PCl_(5) decreases with increase in pressure.

For the reaction : PCl_(5) (g) rarrPCl_(3) (g) +Cl_(2)(g) :