For a reaction 2NOCl(g) Leftrightarrow 2...

For a reaction `2NOCl_(g) Leftrightarrow 2NO_(g)+Cl_(2(g)) , K_c" at "427^@C" is "3 xx 10^(-6)"L mol^(-1)`. The value of `K_p` is nearly

A

`7.5 xx 10^(-5)`

B

`2.5 xx 10^(-5)`

C

`2.5 xx 10^(-4)`

D

`1.72 xx 10^(-4)`

Verified by Experts

The correct Answer is:

D

`2NOCl_(g) Leftrightarrow 2NO_(g)+Cl_(2(g))`
`K_(p) =K_(c) (RT)^(triangle n) =(3 xx 10^(-6)) xx (0.0821 xx 700)=172.41 xx 10^(-6)`
`=1.72 xx 10^(-4)`

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