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N2O4 and NO2 in an equilibrium mixture h...

`N_2O_4 and NO_2` in an equilibrium mixture have partial pressure 0.70 atm and 0.30 atm respectively at `25^@C` and 1 atm. Partial pressure of `N_2O_4` at equilibrium at 9.0 atm and `25^@C` is

A

0.77 atm

B

1.01 atm

C

6. atm

D

8.69 atm

Text Solution

Verified by Experts

The correct Answer is:
C
`"Initially "underset(1)(N_(2)O_(4(g)) Leftrightarrow underset(0)(2NO_(2(g))`
At equilibrium `" (1-x) 2x"`
Total gaseous moles at equilibrium =1-x+2x=1+x
Now, `p_(N_(2)O_(4))=0.7 =(1-x)/(1+x) xx 1`
From above calculation, `x=(0.3)/(1.7)=0.176`
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