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The pH of the solution containing 10 mL ...

The pH of the solution containing 10 mL of 0.1 N NaOH and 10 mL of 0.05 N `H_2SO_4` would be

A

1

B

0

C

7

D

`gt 7`

Text Solution

Verified by Experts

The correct Answer is:
D
Number of milliequivalents of NaOH =Normality `xx " volume (mL)"=0.1 xx 10=1`
Number of milliequivalents of `H_(2)SO_(4)=0.05 xx 10=0.5`
0.5 milliequivalents of `H_(2)SO_(4)` gets neutralized with 0.5 milliequivalents of NaOH thus resulting solution contains 0.5 milliequivalents of NaOH. Hence solution will be basic with `pH gt 7`.
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