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At 298 K, the pH of 0.23 M weak acid HX ...

At 298 K, the pH of 0.23 M weak acid HX (ionization constant `= 7.3 xx 10^(-6))` would be

A

11.47

B

2.88

C

3.88

D

4.88

Text Solution

Verified by Experts

The correct Answer is:
B
For weak acid `alpha=sqrt(K_a/C)`
`[H^+]=C alpha =sqrt(K_a xx C)=sqrt(7.3 xx 10^(-6) xx 0.23)=1.29 xx 10^(-3)`
`pH =-log H^+ =log ""(1)/(H^+)=log ""(1)/(1.29 xx 10^(-3))=2.88`
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