If the solubility of Ca(OH)2" is "sqrt3,...

If the solubility of `Ca(OH)_2" is "sqrt3,` the solubility product of `Ca(OH)_2` is

A

3

B

37

C

`sqrt3`

D

`12sqrt3`

Verified by Experts

The correct Answer is:

D

`Ca(OH)_2 Leftrightarrow underset(s)(Ca^(2+)) +underset(2s)(2OH^(-))`
`K_(sp)=(s) (2s)^2 =4s^3, s=sqrt3`
`K_(sp)=4(sqrt3)^3 =12 sqrt3`

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