The pKb for fluoride ion at 25^@C is 10....

The `pK_b` for fluoride ion at `25^@C` is 10.83, the ionisation constant of hydrofluorie acid at this temperature is

A

`1.74 xx 10^(-5)`

B

`3.52 xx 10^(-5)`

C

`6.76 xx 10^(-4)`

D

`5.38 xx 10^(-2)`

Verified by Experts

The correct Answer is:

C

Applying `K_a=K_w/K_b`
`pK_b=-log K_b=10.83, log""1/K_b=10.83`
`K_b=1.479 xx 10^(-11)`
`rArr K_a=(10^(-14))/(1.479 xx 10^(-11))=6.76 xx 10^(-4)`

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