Assuming complete ionization, the pH of 0.1M HCl is 1. The molarity of `H_2SO_4` with the same pH is

Options

A. 0.1
B. 0.2
C. 0.05
D. 2

Answer

C

Explanation

`[H^+]` in 0.1 M HCl=0.1 M
For some `pH, [H^+]" in "H_(2)SO_(4)=0.1M`
One mole of `H_2SO_4` gives 2 moles of `H^+` ions
`H_(2)SO_(4) to 2H^+ +SO_(4)^(2-)`
0.1 M `[H^+]` will be given by `=(0.1)/2=0.05 MH_(2)SO_(4)`