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In the dissociation of PCl5 PCl(5(g)) ...

In the dissociation of `PCl_5`
`PCl_(5(g)) Leftrightarrow PCl_(3(g)) +CL_(2(g))`
if as if the degree of dissociation is `alpha` at equilibrium pressure P, then the equilibrium constant for the reaction is

A

`K_p=(alpha^2)/(1+alpha^2P)`

B

`K_(p)=(alpha^2 P^2)/(1-alpha^2)`

C

`K_(p)=(P^2)/(1-alpha^2)`

D

`K_(p)=(alpha^2P)/(1-alpha^2)`

Text Solution

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The correct Answer is:
D
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