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Using the Gibbs energy change, triangleG...

Using the Gibbs energy change, `triangleG^@=+63.3` kJ for the following reactions
`Ag_(2)CO_(3(g)) Leftrightarrow 2Ag_(aq)^(+) CO_(3(aq))^(2-)`
the `K_(sp) of Ag_(2)CO_(3(s))` in water at `25^@C` is

A

`3.2 xx 10^(-26)`

B

`8.0 xx 10^(-12)`

C

`2.9 xx 10^(-3)`

D

`7.9 xx 10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
B
`triangleG^@ =-2.303 RT log K_(sp)`
`63.3 xx 10^(3) J=-2.303 xx 8.314 xx 298 log K_(sp)`
`63.3 xx 10^(3) j =-5705.84 log K_(sp)`
`log K_(sp)=-(63.3 xx 10^3)/(5705.84)=-11.09`
`K_(sp)="antilog (-11.09)=8.128 "xx 10^(-12)`
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