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The solubility of AgCl(s) with solubilit...

The solubility of `AgCl_(s)` with solubility product `1.6 xx 10^(-10)` in 0.1 M NaCl solution would be

A

`1.26 xx 10^(-5)M`

B

`1.6 xx 10^(-9)M`

C

`1.6 xx 10^(-11)M`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
B
Let s be the solubility of AgCl in moles per litre.
`AgCl_((aq)) Leftrightarrow Ag_((aq))^+ +Cl_((aq))^+`
(0.1 M NaCl solution also provides 0.1 M `Cl^(-)` ions)
`K_(sp)=[Ag^(+)] [Cl^(-)]`
`1.6 xx 10^(-10)=s(s+0.1)`
`1.6 xx 10^(-10)=s(0.1)`
`s=(1.6 xx 10^(-10))/(0.1)=1.6 xx 10^(-9)M`
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