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Following solutions were prepared by mix...

Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations:
A. `60mL ""M/(10) HCl+"40 mL "M/(10)NaOH`
B. `55mL ""M/(10) HCl+"45 mL "M/(10)NaOH`
C. `75mL ""M/(5) HCl+"25 mL "M/(5)NaOH`
D. `100mL ""M/(10) HCl+"100 mL "M/(10)NaOH`
pH of which one of them will be equal to 1?

A

B

B

A

C

D

D

C

Text Solution

Verified by Experts

The correct Answer is:
D
`pH =1, so [H^+]=10^(-1)`
For acid base mixture `N_(1)V_(1)-N_(2)V_(2)=N_(3)V_(3)`
(For NaOH and HCl, Normality =Molarity)
`B. M_(2) (H^+) =(55 xx 1/(10)-45 xx (1)/(10))/(100)=(1)/(100)=10^(-2) M, i.e, pH =2`
`C. M_(3)(H^+)=(75 xx 1/5 -25 xx 1/5)/(100)=10^(-1)M i.e, pH =1`
D. `M_(4) (H^+)=(100 xx 1/(10) -100 xx 1/(10))/(200)=0, i.e, pH =17`
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