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The solubility of BaSO4 in water 2.42 xx...

The solubility of `BaSO_4` in water `2.42 xx 10^(-3)"g L"^(-1)` at 298K. The value of its solubility product `(K_(sp))` will be (Given molar mass of `BaSO_(4)="233 g mol"^(-1))`

A

`1.08 xx 10^(-10)" mol"^2 L^(-2)`

B

`1.08 xx 10^(-12)" mol"^2 L^(-2)`

C

`1.08 xx 10^(-14)" mol"^2 L^(-2)`

D

`1.08 xx 10^(-8)" mol"^2 L^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A
Solubility of `BaSO_4, s=(2.42 xx 10^(-3))/(233)" mol L"^(-1)`
`=1.04 xx 10^(-5)" mol L"^(-1)`
`BaSO_4` ionizes completely in the solution as : `K_(sp)=[Ba^(2+)] [SO_(4)^(2-)]=s^2`
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