When sodium reacts with excess of oxygen...

When sodium reacts with excess of oxygen, oxidation number of oxygen changes from

A

0 to-1

B

0 to - 2

C

`-1` to-2

D

` +` 1 to -1

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The correct Answer is:

A

`underset(O.N. =0)underset(darr)(2Na + O_2"(excess)") to underset(O.N. =-1) underset(darr)(Na_2O_2)`

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