Which one of the followings has maximum number of atoms ?

Options

A. 1 g of `Ag_((s))` [Atomic mass of Ag = 108]
B. 1 g of `Mg_((s))` [Atomic mass of Mg = 24]
C. 1 g of `O_(2(g))` [Atomic mass of O = 16]
D. 1 g of `Li_((s))` [Atomic mass of Li = 7]

Answer

D

Explanation

1 mole of substance = `N_(A)` particles
108 g of Ag = `N_(A)` atoms
`rArr` 1 g of Ag = `N_(A)/108` atoms
24 g of Mg = `N_(A)` atoms
`rArr` 1 g of Mg =`N_(A)/24` atoms
32 g of `O_(2)=N_(A)` molecules `=2N_(A)` atoms
`rArr` 1 g of `O_(2)=N_(A)/16` atoms
7 g of Li `=N_(A)` atoms
`rArr` 1 g of `Li=N_(A)/7` atoms
Therefore, 1 g of `Li_((s))`, has maximum number of atoms.