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What is the change in oxidation number o...

What is the change in oxidation number of carbon in the following reaction?
`CH_(4(g))+4Cl_(2(g)) rarr C""Cl_((4(l))) +4HCl_((g))`

A

`+4" to "+4`

B

`0" to "+4`

C

`-4" to "+4`

D

`0" to "-4`

Text Solution

Verified by Experts

The correct Answer is:
C
In `CH_(4)`, oxidation number of carbon is -4 while in `C""Cl_(4)`, oxidation number of carbon is +4. Thus, the change in oxidation number of carbon in the given reaction is from -4 to +4.
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