A circle touches the side BC of a `DeltaABC` at a point P and touches AB and AC when produced at Q and R respectively. Show that AQ = 1/2(Perimeter of `DeltaABC`).

A circle touches the side BC of DeltaABC at P and touches AB and AC produced at Q and R respectively. Prove that AQ=1/2(Perimeter of DeltaABC).

A circle is touching the side BC of Delta ABC at P and touching AB and AC produced at Q and R respectively Prove that AQ=(1)/(2) (Perimeter of Delta ABC)

A circle touches the side BC of a Delta ABC at P and also touches AB and AC produced at Q and R, respectively. If the perimeter of Delta ABC = 26.4 cm, then the length of AQ is:

A circle is touching the side BC of ABC at P and touching AB and AC produced at Q and R respectively.Prove that AQ=(1)/(2)(Perimeter of ABC)

A circle touches the side BC of Delta ABC at F and touches AB and AC at D and E, respectively. If AD = 8 cm, then find the perimeter of Delta ABC .

A circle touches the side BC of DeltaABC at D and AB and aC are produced to E and F, respectively. If AB=10cm, AC=8.6 cm and BC=6.4 cm then BE=?

In the given figure, D, E and F are the points where the incircle of the DeltaABC touches F the sides BC, CA and AB respectively. Show that AF+ BD + CE = AE + BF + CD = (perimeter of Delta ABC)

The sides AB,BC and AC of a triangle ABC touch a circle with centre O and radius r at P Q,and R respectively.