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In Fig. 4, a sector OAP of a circle with...

In Fig. 4, a sector OAP of a circle with centre O, containing `angle0`. AB is perpendicular to the radius OA and meets OP produced at B. Prove that the perimeter of shaded region is r.
[tan 0 + sec 0 + `(pi0)/(180^(circ)) -1]`

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The correct Answer is:
[Hint: Perimeter of shaded region = AB + PB + AP, =r `tan theta + r sec theta - r + (pirtheta)/(180)]`
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