If you throw a pair of dice n times, find the probability of getting at least one doublet.[When you get identical members you call it a doublet. You can get a double in six ways: (1,1),(2,2),(3,3),(4,4),(5,5) and (6,6) , thus the probability of getting a doublet is `6/36=1/6`, so that the probability of not getting a doublet in one throw is `5/6]`.

Answer

`1 - ((5)/(6))^(np(n))`