Calculate the work done,in Newton by the gravitational field when a particle is moved along the line 3y+2x=5 in the region of gravitational field E=(2i+3j) Nkg^-1 ,from (1,1)m to (-2,3) m

The gravitational field in a region is given by E = (2 hati + 3 hatj) N//kg . Find the work done by the gravitiational filed when a particle of mass 1 kg is moved on the line 3y+ 2X = 5 from (1 m,1m) to (-2 m, 3m) .

The gravitational field in a region is 10N//kg (hati - hatj) . Find the work done by gravitational force to shift slowly a particle of mass 1kg from point (1m, 1m) to a point (2m,-2m).

If gravitational potential is V = xy^(2) , find the gravitational field at (2,1)

Gravitational potential in x-y plan varies with x and y coordinates as V = x^(2)y+2xy Find gravitational field strength E .

The gravitational field ina region is given by E=(2veci+vecj)Nkg^-1 show that no work is done by the gravitational field when particle is move on the line 3y+2x=5 .

The gravitational field in a region is given by vecE=-(20Nkg^(-1))(hati+hatj) . Find the gravitational potential at the origin (0,0) in J kg^(-1)

Statement-1: Work done in gravitational field in cyclic process is zero. Statement-2: Work done in conservation field does not depend upon path.