An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.

Explanation

`{:("Convex mirror","Object","Image"),(f=+15 cm,u=-10 cm,v=?),(r=2f=+30 cm,,"Nature of image = ?"):}`
Mirror formula : `(l)/(v)+(l)/(u)=(l)/(f)`
`(l)/(v)+(l)/((-10))=(1)/((15)),(l)/(v)=(1)/(15)+(1)/(10), (l)/(v)=(25)/(150) v=+6cm`
`m=-(v)/(u)rArr m=-(6)/((-10))=+0.6`
Magnification (m) `lt 1`, indicates that the image is diminished. The image is formed at a distance of 6 cm to the right of the convex mirror. The + sign signifies this. The height of the image is 0.6 times less than the height of the object. Image formed is erect, virtual and diminished.