Redraw the circuit of question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure potential difference across the 12 `Omega` resistor. What would be the readings in the ammeter and the voltmeter?

Explanation

V = IR
`V_("total")=6V`
`R_("total")=5+8+12=25Omega`
Therefore, I = V/R = 6/25A.
Reading in the voltmeter = V = IR = `6A//25xx12Omega=2.88V`.