A ball falls off a table and reaches the ground in 1 s. Assuming `g=10m//s^(2)`, calculate its speed on reaching the ground and the height of the table.

Explanation

Given :
time (t) = 1 s, `g=10m//s^(2)`
To find : Final speed (v)
Height (h)
Formula : (i) v = u + at
(ii) `s=ut+at^(2)`
Solution :
Ball falls freely from the table
u = 0
a = g
v = u + at ……..(i)
v = 0 + gt
v = (10) (1)
speed = v = 10 m/s
`s=ut+(1)/(2)at^(2)......(ii)`
s = h, u = 0, a = g t = 1
`h=(0)(1)+(1)/(2)xx10xx1^(2)`
Height = h = 5m